Law of Cooling Calculation  

Example:
Calculate the law of cooling of the object for the given details.
Time (t) = 11
Surrounding constant temperature (Ts) = 30
Initial temperature of the object (To) = 10
Core Temperature (T) = 20
Solution:
Apply Formula:
T (t) = Ts + (To  Ts)*e^(k*t)
k = LOG ((2030)/(1030))
k = 0.301029996
EXP (0.301029996*11) = 0.036467641
T (t) = 30+(1030) * 0.036467641 = 29.27064717
T (t) = 29.27064717 = 30
Temperature of the object at time t T(t): 30 (F)